Meiji: Pacers survived four times, and the probability of winning these 4 games is 1 in 1.5 million

June 6th, today's NBA Finals Pacers played against Thunder G1, and Pacers (1) defeated the Thunder 111-110. After the game, NBA reporter Ben Golliver updated social media: "The Pacers have escaped from death four times this year's playoffs.

Bucks led 7 points in the last 35 seconds, with a winning rate of 97.9% (final loss)

Cavaliers led 7 points in the last minute, with a winning rate of 95.9% (final loss)

Knicks led 14 points in the last 3 minutes, with a winning rate of 99.7% (final loss)

Thunder led 9 points in the last 3 minutes , the winning rate is 96.4% (final loss). "

In addition, NBA reporter Tyler Smith added: "The Pacers' winning probability of these four games is 0.3%, 2.1%, 4.1%, and 2.6%. The Pacers' probability of winning all four games in four games = 0.0000006716 This is a probability of one in one million. "

The Thunder's winning probability